Halogen containing clusters N2Br2, N2Br4, S2Br4 and S2Br6 yield penannular inclusion compounds. Issue 47 (4th November 2015)

• Record Type: Journal Article
• Authors: Alshahateet, Solhe F.; Bhadbhade, Mohan M.; Bishop, Roger; Craig, Donald C.; Scudder, Marcia L.
• Is Part Of: CrystEngComm. Volume 17:Issue 47(2015)
• Page Start: 9111
• Page End: 9122
• Publication Date: 2015-11-04
• Subjects: Crystals -- Periodicals; Crystal growth -- Periodicals; Crystallography -- Periodicals; Cristaux -- Périodiques; Cristaux -- Croissance -- Périodiques; Cristallographie -- Périodiques; 548
• DOI: 10.1039/c5ce01838b
• Languages: English
• ISSNs: 1466-8033

Abstract

Abstract : The tetrabromo host molecule forms inclusion compounds by employing heteroatom clusters as linking supramolecular synthons. Abstract : Crystallisation of the tetrahaloaryl host 2, 4, 10, 12-tetrabromo-6, 7, 14, 15-tetrahydro-6, 14-thiacycloocta[1, 2- b :5, 6- b ′]diquinoline7 from benzene, chloroform, 3-methylpyridine, 4-methylpyridine, 2-methylpyridine, or tert -butylcyclohexane, yields a series of closely related inclusion compounds (7 )2 ·(guest) in space group P 1̄. Two host molecules surround a single guest to form a penannular repeat unit in each of these crystal structures. Structural variation arises from the differing guest sizes, shapes and interactions. The corners of four molecular pens are linked by utilising novel S/Br clusters as supramolecular synthons: S2 Br4 for the first four compounds, and S2 Br6 for the latter two cases. The aromatic faces of the repeat units associate through offset π⋯π interactions. Aromatic edge–edge linkage occurs in the former group of compounds by means of N2 Br2 and N2 Br4 clusters, but these are absent in the final two structures. Mesitylene (1, 3, 5-trimethylbenzene) is too wide for penannular inclusion. It yields an alternative layer structure, (7 )·(mesitylene), also in P 1̄. This compound is stabilised by means of host–guest C–H⋯π associations, plus host–host aromatic and S⋯Br⋯Br⋯N interactions.